User Login means that the user enters the user name and password, clicks the login page, does not refresh, and then submits it to the background program using ajax for judgment. If the login succeeds, the system returns real or relevant user information, in this way, the user does not need to log on again.
Php Jquery does not require any new login, so it is easy to write your own
Added a check to determine whether the logon status is displayed after refresh if it is logged on.
Logon page file
Html page
| The Code is as follows: |
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<Script type = "text/javascript" src = "jquery-1.4.3.js" mce_src = "jquery-1.4.3.js"> </script>
<Script type = "text/javascript">
$ (Document). ready (function () {// onload event handler function of DOM
$ ("# Button"). click (function () {// processing function when a button is clicked
Postdata (); // execute the postdata function when the button is clicked.
});
});
Function postdata () {// submit data function
$. Ajax ({// call jquery's ajax Method
Type: "POST", // set the ajax method to submit data
Url: "login_ OK .php", // submit the data to OK. php.
Data: "writer =" + $ ("# writer "). val () + "& pass =" + $ ("# pass "). val (), // input the value in the writer box as the submitted data
Success: function (msg) {// callback after successful submission. The msg variable is output by OK. php.
$ ("# Div2" cmd.html (msg); // if necessary, you can display the value of the msg variable to a DIV element.
}
});
}
</Script>
<Script type = "text/javascript">
<! --
Function init (){
$. Ajax ({
Type: "GET ",
Url: "if_login.php ",
Data: "ts =" + new Date (). getTime (),
Success: function (msg) {// callback after successful submission. The msg variable is output by OK. php.
If (msg = 'true '){
$ ("# Div2" pai.html ("login OK ");
}
}
});
}
// -->
</Script>
<Body onLoad = "init ();">
<Div id = "div2">
<Input name = "writer" id = "writer" type = "text" value = ""/>
<Input name = "pass" id = "pass" type = "password" value = ""/>
<Input type = "submit" name = "button" id = "button" value = "submit"/>
</Div>
</Body>
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Send to file
| The Code is as follows: |
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<? Php
Session_start ();
Require "conn. php ";
$ Username = $ _ POST ['writer'];
$ Password = $ _ POST ['pass'];
Mysql_select_db ($ database_lr, $ lr );
$ SQL = "SELECT * FROM admin WHERE username = '$ username' AND password =' $ password '";
$ Result = mysql_query ($ SQL );
If (mysql_num_rows ($ result)> 0)
{
// Login sucess
$ _ SESSION ['login _ admin'] = "Admin ";
Echo "login OK ";
}
Else
{
// The user ID found
Echo "Login failed, ID error or expired .";
}
?> |
