PHP variable reference Assignment some knowledge

The explanation in the manual is: a simple reference (in other words, "become its alias" or "point to") the original variable. Changing the new variable will affect the original variable and vice versa.
I understand the reference to a person who has taken two names, whether it's a name or a person.
The following two example results are all the same. Deleting or modifying will affect the value of another variable.

 !--? php 
   
     $foo = 
     ' Bob ' ;              
    // assigns 
     ' Bob '  to 
     $foo  
     $bar  = & 
     $foo ;  
    // with 
     $bar  reference 
     $foo  
     $bar  = 
     "My name is $bar" ;                 
    // modify 
     $bar  variable echo 
     $bar ; echo 
     $foo ; 
    //              The value of 
     $foo  has also been modified?>!--? php 
    
      $foo = 
      ' Bob ' ;              
     // assigns 
      ' Bob '  to 
      $foo  
      $bar  = & 
      $foo ;  
     // with 
      $bar  reference 
      $foo  
      $foo  = 
      "My name is $bar" ;                 
     // modify 
      $foo  variable echo 
      $bar , 
      "\ n" ; echo 
      $foo ; 
     // The value of 
      $foo  has also been modified? 
    
    

When you delete a reference, either deleting b or a result does not affect the other variable. Just the equivalent of deleting a name without affecting the variable itself.

  
   0;$b = &$a;  //  echo$a; //0   unset($bunset$bunset($aunset$becho$b; //0 it's OK

When a variable refers to two variables successively, the first reference variable is modified to the second reference. The first reference has no relationship and does not affect each other.

    
     $a = "hihaha";$b = &$a;$c = "eita";$b = &$c;echo$b; // shows "hihaha"

The invocation of a function's address call, executed, is equivalent to changing the referenced variable directly. Over here b the real of the pass-through function is a The memory address where the variable contents of B are located, by changing in the function the value of a can be changed B's value.

functiontest( &$a ){$a10;  return$a;}$b1;test($b);echo$b;//输出11

A reference to the function returns

function &test2(){    $b  0;//申明一个静态变量    $b  =   $b+1;    return$b;}$a = test2();//这条语句会输出　$b的值　为１var_dump($a);$a = test2();//这条语句会输出　$b的值　为2var_dump($a);$a = & test2();//这条语句会输出　$b的值　为3var_dump($a);$a5;$a = test2();//这条语句会输出　$b的值　为6var_dump($a);

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