foreach ($info as $file) {
$CC = $data [' img '] = $file [' Savename '];
Echo basename ('./uploads/42.jpg ', '. jpg ');
$image->open ('./uploads/picture name. jpg ');
$image->thumb (->save) ('./uploads/Picture name. jpg ');
$User = M ("User");
$User->where ("id= ' {$AA} '")->save ($data);
$this->success (' Upload successful ', ' cc ');
I want to change the uploaded image, do not know what to write in the picture name position
Reply to discussion (solution)
Open the original, $file [' Savename ']
As for the thumbnail name, simply add a word in the back, or write a general function, according to the original name to generate a line
Open the original, $file [' Savename ']
As for the thumbnail name, simply add a word in the back, or write a general function, according to the original name to generate a line
$image->open ('./uploads/$file [' savename '].jpg '); Is that what this means?
$BB = $file [' Savepath ']. $file [' Savename '];
$image->open ($BB);
$image->thumb (150,\think\image::image_thumb_center)->save ($BB);
Finally this kind of solution ...