POJ more than 1459 Yuanhui maximum flow

Source: Internet
Author: User

Analysis is here


Nest to the original method is also written well, anyway is similar ....

In fact.... It also wrote the highest-grade pre-flow propulsion ......... .............. It's such a pain in the egg .... However, on this topic, the three methods are all the same ...

Code

#include <cstdio> #include <iostream> #include <cstring> #include <algorithm> #include < vector> #include <string> #include <queue> #include <map> #include <set> #include <cmath > #include <cstdlib>using namespace std, #define INF 0x3f3f3f3f#define PI acos ( -1.0) #define MEM (A, B) memset (A, B, sizeof (a)) typedef pair<int,int> PII;TYPEDEF Long Long ll;//------------------------------const int MAXN = 205;int n,m;struct edge{int to, CAP, rev;//end capacity reverse edge edge (int to_ = 0, int cap_ = 0, int rev_ = 0) {to = To_            ;            Cap = CAP_;      Rev = rev_; }};vector<edge> g[maxn];int level[maxn];//Vertex to source point distance designator int iter[maxn];void Add_edge (int from, int. to, int cap) {Ed      GE Tmp1 (To, Cap, g[to].size ());      G[from].push_back (TMP1);      Edge tmp2 (from, 0, G[from].size ()-1); G[to].push_back (TMP2);}      void BFs (int s) {memset (level,-1, sizeof);      Queue<int> Q;      Level[s] = 0; Q.push (s);      while (!q.empty ()) {int v = q.front ();            Q.pop ();                  for (int i = 0; i < g[v].size (); i++) {edge& e = g[v][i];                  if (E.cap > 0 && level[e.to] < 0) {level[e.to] = Level[v] + 1;                  Q.push (e.to);      }}}}int dfs (int v, int t, int f) {if (v = = t) return F;            for (int& i = iter[v]; i < g[v].size (); i++) {edge& e = g[v][i];                  if (E.cap > 0 && level[v] < level[e.to]) {int d = DFS (e.to, T, Min (E.cap, f));                        if (d > 0) {e.cap-= D;                        G[e.to][e.rev].cap + = D;                  return D; }}} return 0;}      int Max_flow (int s, int t) {int flow = 0; for (;;)            {BFS (s);            if (Level[t] < 0) return flow;            memset (ITER, 0, sizeof (ITER));  int F;          while ((f = DFS (S, T, INF)) > 0) {flow + F; }}}//------------------above is the maximum flow template part correctly----------------------int NP, nc;void init () {for (int i = 0; i < MAXN; I      + +) G[i].clear ();      int U, V, W;      Char ch;            for (int i = 1; I <= m; i++) {while (scanf ("%c", &ch)) {if (ch = = ' (') break;            } scanf ("%d,%d%c%d", &u,&v,&ch,&w);      Add_edge (U, V, W);            } for (int i = 1; I <= np; i++) {while (scanf ("%c", &ch)) {if (ch = = ' (') break;            } scanf ("%d%c%d", &u, &ch, &w);      Add_edge (N, u, W);            } for (int i = 1; I <= NC; i++) {while (scanf ("%c", &ch)) {if (ch = = ' (') break;            } scanf ("%d%c%d", &v, &ch, &w);      Add_edge (V, N+1, W);      } int ans = Max_flow (n, n+1); printf ("%d\n", ans);} int main () {while(scanf ("%d%d%d%d", &AMP;N,&AMP;NP, &AMP;NC, &m)! = EOF)      {init (); } return 0;}



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POJ more than 1459 Yuanhui maximum flow

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