[POJ2406] Power Strings

Source: Internet
Author: User

Title Link: http://poj.org/problem?id=2406

Description

Given Strings A and b we define a*b to be their concatenation. For example, if a = "abc" and B = "Def" then a*b = "abcdef". If we think of concatenation as multiplication, exponentiation by a non-negative integer are defined in the normal way:a^0 = "" (The empty string) and a^ (n+1) = A * (a^n).

Input

Each test case was a line of input representing S, a string of printable characters. The length of S'll be is at least 1 and would not exceed 1 million characters. A line containing a period follows the last test case.

Output

For each s should print the largest n such, that s = a^n for some string a.

Sample Input

Abcdaaaaababab.

Sample Output

143

Hint

This problem have huge input, use scanf instead of CIN to avoid time limit exceed.

Source

Waterloo local 2002.07.01 give you a string, this string is inside of a substring loop n times obtained, beg for this n. KMP Circulation section, two formulas: if n% (n-pre[n] = = 0 indicates the existence of a cyclic section, the number of cycles is N/(N-pre[n])
1#include <cstdio>2#include <cstdlib>3#include <cstring>4#include <algorithm>5#include <iostream>6#include <cmath>7#include <queue>8#include <map>9#include <stack>Ten#include <list> One#include <vector> A  - using namespacestd; -  the Const intMAXN =66666666; - intna, NB; - CharA[MAXN]; - CharB[MAXN]; + intPRE[MAXN]; -  + //B is the pattern string, a is the target string A voidGetpre (Char*b,int*pre) { at     intJ, K; -pre[0] = -1; -j =0; -K =-1; -      while(J <nb) { -         if(k = =-1|| B[J] = =B[k]) { inJ + +; -k++; toPRE[J] =K; +         } -         Else { theK =Pre[k]; *         } $     }Panax Notoginseng } -  the intKMP () { +     intAns =0; A     inti =0; the     intj =0; + Getpre (b, pre); -      while(I <na) { $         if(j = =-1|| A[i] = =B[j]) { $i++; -J + +; -         } the         Else { -j =Pre[j];Wuyi         } the         if(J = =nb) { -ans++; Wu         } -     } About     returnans; $ } -  - intMain () { -Freopen ("inch","R", stdin); A      while(~SCANF ("%s", b) && strcmp (".", B)) { +NB =strlen (b); the Getpre (b, pre); -         intloop = NB-PRE[NB]; $         if(nb% loop = =0) { theprintf"%d\n", NB/loop); the         } the         Else { theprintf"1\n"); -         } in     } the}

[POJ2406] Power Strings

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