4 Values whose Sum is 0
| Time Limit: 15000MS |
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Memory Limit: 228000K |
| Total Submissions: 16970 |
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Accepted: 4954 |
| Case Time Limit: 5000MS |
Description
The SUM problem can formulated as Follows:given four lists A, B, C, D of an integer values, compute how many quadruplet ( A, B, C, D) ∈a x B x C x D is such that A + B + c + d = 0. In the following, we assume this all lists has the same size n.
Input
The first line of the input file contains the size of the lists n (this value can be as large as 4000). We then had n lines containing four integer values (with absolute value as large as 228) that belong respectively to A, B, C and D.
Output
For each of the input file, your program have to write the number quadruplets whose sum is zero.
Sample Input
6-45 22 42-16-41-27 56 30-36 53-37 77-36 30-75-4626-38-10 62-32-54-6 45
Sample Output
5
Hint
Sample Explanation:indeed, the sum of the five following quadruplets is zero: (-45,-27, 42, 30), (26, 30,-10,-46), (-3) 2, 22, 56,-46), (-32, 30,-75, 77), (-32,-54, 56, 30).
Test instructions: Topic given a matrix of n*4, and then asked you to select a number in each column, so that the sum of four number of 0 of the combination of how many.
Analysis: Binary enumeration, bidirectional search. The amount of data on the topic is larger, and violence definitely expires. So we have to find another way to do it. We can preprocess the ab[k]=a[i]+b[j],cd[k]=c[i]+d[j], then sort the CD Array (sort (cd,cd+k)), then enumerate the elements of the AB array, and search on the CD array for two points. If there is a corresponding number in the CD array, then add the number, how to get the number? Here you can skillfully apply the two functions in the STL Library: Lower_bound (), Upper_bound (). A detailed explanation of these two functions is in: http://blog.csdn.net/jhgkjhg_ugtdk77/article/details/46229645
Title Link: http://poj.org/problem?id=2785
Code Listing:
#include <set> #include <map> #include <cmath> #include <queue> #include <stack> #include <ctime> #include <cctype> #include <string> #include <cstdio> #include <cstdlib> #include <cstring> #include <iostream> #include <algorithm>using namespace std;typedef long Long ll;typedef unsigned long long ull;typedef unsigned int uint;const int MAXN = 4000 + 5;int n;int a[maxn],b[maxn];int c[maxn],d[maxn];i NT A_b[maxn*maxn],c_d[maxn*maxn];void input () {scanf ("%d", &n); for (int i=0;i<n;i++) {scanf ("%d%d%d%d", &a[i],&b[i],&c[i],&d[i]); }}void solve () {int index=0; for (int. i=0;i<n;i++) {for (int j=0;j<n;j++) {a_b[index]=a[i]+b[j]; C_D[INDEX]=C[I]+D[J]; index++; }} sort (C_d,c_d+index); ll Ans=0; for (int i=0;i<index;i++) {int number=-a_b[i]; ans+= (LL) (Upper_bound (C_d,c_d+index,number)-lower_bound (C_d,c_d+index,number)); } printf ("%i64d\n", ans);} int main () {input (); Solve (); return 0;}
Poj_2785_4 Values whose Sum is 0 (lower_bound,upper_bound)