Problem c:c language exercises integer ordering __c language

"tests are to indicate the existence of a bug rather than not exist"--edsger Dijkstra Description

Sorts and outputs n integers using a pointer to a pointer. Requires that the sort be written as a single function. Integers and n are entered in the main function. Finally, the output is in the main function.

Input

N and N integers

Output

The sorted integer

Sample Input

5
4 3 2 1 5

Sample Output

1 2 3 4 5

HINT

The main function is given as follows, and the following main functions are not required for submission

/* C code * *

int main ()
{
void sort (int **,int);
int i,n,data[20],**p,*pstr[20];
scanf ("%d", &n);
for (i=0; i<n; i++)
pstr[i]=&data[i];
for (i=0; i<n; i++)
scanf ("%d", pstr[i]);
P=PSTR;
Sort (p,n);
for (i=0; i<n; i++)
printf ("%d", *pstr[i]);
return 0;
}


/* C + + code * *
int main ()
{
void sort (int **,int);
int i,n,data[20],**p,*pstr[20];
cin>>n;
for (i=0; i<n; i++)
pstr[i]=&data[i];
for (i=0; i<n; i++)
cin>>*pstr[i];
P=PSTR;
Sort (p,n);
for (i=0; i<n; i++)
cout<<*pstr[i]<< "";
return 0;
}

Source:

#include <iostream>
 
using namespace std;
 
void sort (int **p,int n) {
    int m,f;
    for (int i=0;i<n;i++) {
        m=* (*p+i);
        f=i;
        for (int j=i+1;j<n;j++) {
            if (m>* (*p+j)) {
                m=* (*p+j);
                F=j
            }
        }
        * (*p+f) =* (*p+i);
        * (*p+i) =m
 
    }
}
int main ()
{
    void sort (int **,int);
    int i,n,data[20],**p,*pstr[20];
    cin>>n;
    For (i=0 i<n; i++)
        pstr[i]=&data[i];
    For (i=0 i<n; i++)
        cin>>*pstr[i];
    P=pstr;
    Sort (p,n);
    for (i=0; i<n; i++)
        cout<<*pstr[i]<< "";
    return 0;
}