Python calls C + +

/***gcc-o libpycall.so-shared-fpic pycall.c*/  #include <stdio.h>  #include <stdlib.h>  int Foo (int a, int b)  {    printf ("You input%d and%d\n", A, b);    return a+b;  }  

Python calls the file for the dynamic library: pycall.py

Import ctypes  ll = ctypes.cdll.LoadLibrary   lib = ll ("./libpycall.so")    Lib.foo (1, 3)  print ' * * * finish*** '  

Python calls C + + (Class) dynamic-link library

extern "C" is required to assist, that is, you can only call the C function, you cannot call the method directly, but you can parse the C + + method. Instead of using extern "C", the built-in dynamic-link library does not have a symbol table for these functions.

#include <iostream>using namespace Std;class testlib{public    :        void Display ();        void display (int a);}; void TestLib::d isplay () {    cout<< "first display" <<ENDL;} void TestLib::d isplay (int a) {    cout<< "Second display:" <<A<<ENDL;} extern "C" {    TestLib obj;    void display () {        obj.display ();       }    void Display_int () {        obj.display (2);       }}

g++ compilation generates a dynamic library libpycall.so:g++-O libpycallclass.so-shared-fpic pycallclass.cpp.
Python calls the file for the dynamic library: pycallclass.py

Import Ctypesso = Ctypes.cdll.LoadLibrary lib = so ("./libpycallclass.so") print ' Display () ' Lib.display () print ' Display ( (+) ' Lib.display_int (100)

Reprint: http://blog.csdn.net/taiyang1987912/article/details/44779719

Python calls C + +