Press Ctrl + F to use a regular expression. For example
Original article
<A href = "{site_url} s/goelia % 2f % B8 % E8 % C0 % F2 % E6 % AB/" target = "_ blank"> goelia/Gloria </> </DD> <a href = "{site_url} s/% BC % be % Ba % F2 % B7 % E7/" target = "_ blank"> seasonal event </a> </DD> <a href = "{site_url} s/Mickey % 2f % C3 % D7 % C6 % E6/" target = "_ blank"> Mickey/Mickey </a> </DD> <a href = "{site_url} s/% C0 % CB % C2 % Fe % D2 % BB % C9 % ed/"target =" _ blank "> Lang Man </a> </DD> <a href =" {site_url} s/Miss + sixty/"Target = "_ blank"> Miss Sixty </a> </DD> <a href = "{site_url} s/% CF % E3 % D3 % B0/" Target = "_ blank"> Xiangying </a> </DD> <a href = "{site_url} s/jorya % 2f % D7 % BF % D1 % C5/ "Target =" _ blank "> jorya/Zhuo ya </a> </DD> <a href =" {site_url} s/ports % 2f % B1 % a6 % d7 % CB/"target =" _ blank "> ports/baozi </a> </DD> <a href =" {site_url} s/Gucci % 2f % b9 % C5 % C6 % E6/"target =" _ blank "> Gucci/Gucci </a> </DD> <a href =" {site_url} s/ jeanswest % 2f % D5 % E6 % Ce % AC % CB % B9/"target =" _ blank "> jeanswest/jevis </a> </DD>
I want to replace all the href attributes of a with {site_url} TS/{url_base64_encode ('duoyi')}/, because the previous parts of the href attributes in the preceding text are the same, the content behind S/is different, and it is basically a number plus a letter plus %. We use assense \ s + to match strings that do not contain blank characters. Then, "Enter in search"
{Site_url} s/\ s +/
OK, click replace all