Returns an array from the function.

Source: Internet
Author: User

 
1 Char* Vector_advance (Char* Val)

Most people encounter previous functions. The biggest problem is who releases resources?

Let's look at another function.

 
1 Char(& Vector_advance (Char(&VaR)[4]) [4]

This function indicates that vector_advance is the function name. It receives an array containing four elements and returns an array containing four elements, which is indeed a bit weird,

Easy to understand

1Typedef mycharChar[4];2Mychar & vector_advance (mychar &VaR);

Barely acceptable. If you use the boost library's array library, it will be much more convenient

 
1# Include <boost \ array. HPP>2Typedef boost: <array <Char,4>Array4_t;3Array4_t & vector_advance (array4_t &VaR);

 

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