I 've been crazy recently. I think of incentive and allocation...
I accidentally visited this and thought it was good. I posted it here:
First, I declare that I am not interested in gambling, and I have no research on gambling. The twoAlgorithmFrom the perspective of a novel, I feel a little interesting. Many people know the mathematical knowledge, but not many people can really understand these two algorithms.
The first algorithm is very simple. For example, you can understand it. Bet is required for gambling. Sometimes the bet amount is the key to winning or losing. If you place a bet in the following way, you can never lose. For example
I got 1 yuan, but I'm not lucky. If I lose, it doesn't matter. I bet 2 yuan for the second time. If I lose again, I will lose 4 yuan for the third time, and so on until I win. To sum up, it means that once you lose, the pressure will be doubled, and if you win, you will be able
The loss of one hand is supplemented, and the loss of another one is multiplied. In this way, if you win the last time, you will make up for all the previous losses. Is it easy?
The first algorithm is the strategy used when you lose. The second algorithm is the opposite. It is the BET method used when you win. It starts from 1 RMB. If you win, you can continue to press 1 RMB. If you win, you can press 2 RMB to win again.
Press 3 yuan, and so on: 5, 8, 13... the sum of the money you press each time is the sum of the previous two. If you lose, it is equivalent to the first two did not win, and the money you win is your own. It is also very simple.
How do you think that people who lose gambling money are all fools? This is simply the two axes in Li Yun's hand. When God kills God, And when ghosts kill ghosts, why is there no money to win? Is that true? The old ancestor warned me long ago
Guys: there is no free lunch in the world, and God won't leave it unprovoked. Everyone is doing it, and their mathematical skills are not bad. If you are interested, you can write a small one.ProgramSimulate it and everything will be clear.
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