Silverlight 4 page Jump Overview

// Silverlight page Jump
// (Application. Current. rootvisual as icontent). content = new dragcontrol ();
// Normal page Jump
Htmlwindow html = Htmlpage. window;
// Html. navigate (New uri (" Http://www.0379zd.com ")); // Normal website
Html. navigate ( New Uri ( " ../Index. aspx " , Urikind. Relative )); // Relative Path

Reference 1: Method 1: jump to a webpage
Htmlwindow html = htmlpage. window;
Html. navigate (New uri (item. link_page.trim (), urikind. Relative), "_ blank ");

// System. Windows. browser. htmlpage. popupwindow (New uri (htmlpage. Document. documenturi, item. link_page.trim (), "_ blank", null );

Method 2: Jump to the XAML page
This. content = new about ();

Method 3: The frame jumps to item. link_page.trim (), which indicates the XAML name e. g:/views/home.
Events = new system. Uri (item. link_page.trim (), urikind. Relative );
This. contentframe. Source = events;

Framework
<Navigation: frame X: Name = "contentframe" style = "{staticresource contentframestyle }"
Source = "/views/about" navigated = "contentframe_navigated" navigationfailed = "contentframe_navigationfailed">
<Navigation: frame. urimapper>
<Urimapper: urimapper>
<Urimapper: urimapping uri = "" mappeduri = "/views/home. XAML"/>
<Urimapper: urimapping uri = "/views/{pagename}" mappeduri = "/views/{pagename}. XAML"/>
<Urimapper: urimapping uri = "/{pagename}" mappeduri = "/{pagename}. XAML"/>
</Urimapper: urimapper>
</Navigation: frame. urimapper>
</Navigation: frame>
Link
<Hyperlinkbutton X: Name = "userid" navigateuri = "/views/home" style = "{staticresource linkstyle}" targetname = "contentframe"/>