Solution to source # N in PHP

Recently, PHP queries often encounter problems such as source #4 or source #5. Below is a good solution. You can try it.

Recently, PHP queries often encounter problems such as source #4 or source #5. Below is a good solution. You can try it.

Recently, PHP queries often encounter problems such as source #4 or source #5, that is, a query operation through mysql_query ($ sql1, the returned result is not a desired field but a source. I checked some materials online and said "resource". Although I still don't know the principle of this situation ,, but the solution is available. The following code solves the problem:

The Code is as follows:

$ Result2 = mysql_query ("SELECT imagePath FROM anymediainfo WHERE schoolId = 1 AND id = $ random ");
$ Row = mysql_fetch_object ($ result2 );
$ ImageUrl = $ row-> imagePath;

As shown in the code above, after the first query, use the mysql_fetch_object function to obtain a row from the result as the object, and then obtain the desired field in this row. I doubt that the cause of this problem is still tangled.