Some tips for using replace in Javascript Regular Expressions.

Regular Expressions are often used, but they are basically used to verify the rationality of a string. For example:

VaR M = "12345 ";

VaR n =/^/d + $ /;

If (N. Test (M) Alert ('OK ');

Today I have read an example about using regular expressions in the replace method, which is very valuable and can be easily implemented, such as the lenb and trim methods.

I Want To sum up not this, but replace the pattern with $ in replace, for example:

VaR M = eval ("/(northsnow) +/g ");

VaR n = "I am northsnow, I come from Jilin ";

VaR t = n. Replace (M, "<B> $1 </B> ");

Alert (N );

The result is as follows: I am <B> northsnow </B>, I come from Jilin ";

The matching results in the brackets are extracted and put into the $ variable. $1 stores the matching of the first pattern, $2 stores the matching of the second pattern, and so on.

For example:

VaR M = "northsnow is a good man ";

VaR n = M. Replace (/s) ([A-Z] +)/g, "$1 ")

Result: northsnow

VaR n = M. Replace (/s) ([A-Z] +)/g, "$2 ")

Result: northsnowisagoodman

In addition, there is a/num that can be used. The num here is an integer, which indicates that the num-th mode is put here.

If (.)/1, it indicates two consecutive repeated characters.

If (.)/D */1 represents two identical characters with N numbers in the middle, N> = 0

Here is an example. As long as you have mastered the skills, you can accumulate experience through practice.