The Chinese character obtains the corresponding phonetic alphabet, searches the Chinese characters in the map through the phonetic alphabet, the reverse map multiple pack into the list

Need to use Pingyin4j.jar

Import Net.sourceforge.pinyin4j.PinyinHelper;
Import Net.sourceforge.pinyin4j.format.HanyuPinyinCaseType;
Import Net.sourceforge.pinyin4j.format.HanyuPinyinOutputFormat;
Import Net.sourceforge.pinyin4j.format.HanyuPinyinToneType;
    
    
Import Net.sourceforge.pinyin4j.format.HanyuPinyinVCharType; public class Pingyin {/** * converts Chinese characters to full spell * * @param src * @return string/public static string Getpinyin (St 
Ring src) {char[] T1 = null; 
T1 = Src.tochararray (); 
System.out.println (t1.length); 
string[] t2 = new String[t1.length]; 
System.out.println (t2.length); 
Set the format of Chinese pinyin output hanyupinyinoutputformat t3 = new Hanyupinyinoutputformat (); 
T3.setcasetype (hanyupinyincasetype.lowercase); 
T3.settonetype (Hanyupinyintonetype.without_tone); 
T3.setvchartype (HANYUPINYINVCHARTYPE.WITH_V); 
String t4 = ""; 
int t0 = t1.length; 
try {for (int i = 0; i < t0 i++) {//Judge whether it is Kanji character//System.out.println (T1[i]); if (character.tostring (T1[i]). Matches ("[\\u4e00-\\u9fa5]+")) {
T2 = Pinyinhelper.tohanyupinyinstringarray (t1[i], T3)//To save a few of the Chinese characters to the t2 array t4 + = t2[0];//Remove the first pronunciation of the Chinese spelling and connect to the string T4 after} else
{//If it is not a kanji character, remove the character directly and connect to the string t4 after T4 + = character.tostring (T1[i]);} 
catch (Exception e) {//TODO auto-generated catch block E.printstacktrace (); 
return t4; /** * Extracts the first letter of each kanji * @param str * @return string/public static string Getpingyinheadchar (String str) {Strin 
G convert = ""; 
for (int j = 0; J < Str.length (); j + +) {char word = Str.charat (j);
Extracts the first letter of Chinese characters string[] Pinyinarray = Pinyinhelper.tohanyupinyinstringarray (word, NULL); 
if (Pinyinarray!= null) {convert + + pinyinarray[0].charat (0); 
else {convert + + word;
} return to convert;  /** * Converts a string to ASCII * @param cnstr * @return string/public static string Getcnascii (String cnstr) {StringBuffer 
Strbuf = new StringBuffer (); 
Converts a string to a byte sequence byte[] BGBK = Cnstr.getbytes (); for (int i = 0; i < bgbk.length i++) {//System.out.println (integer.tohexstring (bgbk[i) &amP 
0xFF)); 
Converts each character to an ASCII code strbuf.append (integer.tohexstring (bgbk[i) & 0xff)); 
return strbuf.tostring ();
public static void Main (string[] args) {String cnstr = "People's Republic of China";
System.out.println (Getpinyin (cnstr));
System.out.println (Getcnascii (cnstr)); 
    
System.out.println (Getpingyinheadchar (cnstr)); }
    
}

More Wonderful content: http://www.bianceng.cnhttp://www.bianceng.cn/Programming/sjjg/

Find Chinese characters in a map by pinyin

Import java.util.ArrayList;
Import Java.util.HashMap;
Import Java.util.Iterator;
Import java.util.List;
Import Java.util.Map;
Import Java.util.Scanner;
Import Java.util.Set;
    
    
Import Java.util.Map.Entry; public class Alphafindword {/** * @param args/@SuppressWarnings ("unchecked") public static void main (string[ ] args) {map<string, string> map=new hashmap<string,string> (); Map.put ("Open", "ZK"); Map.put ("Maniac", "ZK"); Map
. Put ("Andy Lau", "LDH");
Map.put ("Jacky Cheung", "Zxy");
Map.put ("Leehom Wang", "WLH");
    
Map.put ("Deng Zi qi", "dzq");
    
Map.put ("Comfortable", "SC");
Map<string,list> map2=new hashmap<string,list> ();
Set Set=map.entryset ();
Iterator It=set.iterator ();
    
while (It.hasnext ()) {map.entry<string,string> entry= (entry<string, string>) It.next ();
    
List Lst=map2.get (Entry.getvalue ());
if (lst==null) {lst=new ArrayList (); Map2.put (Entry.getvalue (), LST);} lst.add (Entry.getkey ());
} while (true) {Scanner scanner=new Scanner (system.in); String Str=scanner.nextline ();
SYSTEM.OUT.PRINTLN (Map2.get (str));
    
if (Str.equals ("Exit")) {break;}} }
    
    
}

Author: csdn Blog u010026901