The difference analysis and example _javascript technique of three-mesh operator and if else in JS

Today wrote a picture of the little demo, used to judge

first try the If Else, the code is as follows:

Copy Code code as follows:

if (n >= count-1) {
n = 0;
}else{
n + +;
}

Then the code is finished, ready to optimize the code, the paragraph changed to the three-mesh operator of the wording

Copy Code code as follows:

n = n >= (count-1)? n=0:n++

The results are completely different.

Then we studied the difference between the two, summed up as a sentence: three mesh operation has a return value, if else no return value

The following tests were done:

Copy Code code as follows:

var n=1;
if (n>1) {
n=0;
}else{
n++;
}
Console.log (n);

Output Result: 2

Three mesh operations are as follows:

Copy Code code as follows:

var n=1;
n = n>1?0:n++;
Console.log (n);
The output is: 1

Insert something else: the difference between ++n and n++: Simply put, it's all n from 1. The difference is that n++ is executed after the statement is added to 1, and ++n do the n+1 before executing the following statement

So what about ++n?

If Else statement

Copy Code code as follows:

var n=1;
if (n>1) {
n=0;
}else{
++n;
}
Console.log (n);
Output Result: 2

The results of the three-mesh operation

Copy Code code as follows:

var n=1;
n = n>1?0: ++n;
Console.log (n); The output is: 2

can see if else and three mesh operation of the difference between ~ ~ ~

n++ and ++n in this validation, there is no difference, because if else is the result of the calculation, does not return n, no return value

But for the three-mesh operation, the n++ returns the n value of n itself, ++n returns the value of n as the result of n+1

Read this article, the small partners are not the JS in the three-mesh operator and if else has a new understanding of it.