The Go language implementation transforms []string into []byte

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The Go language implementation transforms []string into []byte

Suppose you want to implement the conversion of the Go language string array to a byte array. The demo functions are as follows:

func convertStringsToBytes(){    stringContent := []string{"通知中心","perfect!"}    byteContent := "\x00"+ strings.Join(stringContent, "\x02\x00")  // x20 = space and x00 = null    fmt.Println([]byte(byteContent))    fmt.Println(string([]byte(byteContent)))}

Full code:

package main import (    "fmt"    "strings" ) func convert(){    stringSlice := []string{"通知中心","perfect!"}    stringByte := "\x00" + strings.Join(stringSlice, "\x20\x00") // x20 = space and x00 = null    fmt.Println([]byte(stringByte))    fmt.Println(string([]byte(stringByte))) } func main() {    convert() }

Operation Result:

[0 233 128 154 231 159 165 228 184 173 229 191 131 2 0 112 101 114 102 101 99 116 33] 通知中心  perfect!

This is the simplest method, and there is another way to achieve the same effect. It is primarily implemented using coding mechanisms.

 package main import (    "bytes"    "encoding/gob"    "fmt" )func convert（）{    stringSlice := []string{"通知中心","perfect!"}    buffer := &bytes.Buffer{}    gob.NewEncoder(buffer).Encode(stringSlice)    byteSlice := buffer.Bytes()    fmt.Printf("%q\n", byteSlice)    fmt.Println("---------------------------")    backToStringSlice := []string{}    gob.NewDecoder(buffer).Decode(&backToStringSlice)    fmt.Printf("%v\n", backToStringSlice)} func main() {    convert() }

Welcome you!