The implementation of the method and interface in "Golang Foundation" Go language

This is a creation in Article, where the information may have evolved or changed.

Let's look at an interview question: Can the following code compile the past? Why?

package mainimport (    "fmt")type People interface {    Speak(string) string}type Stduent struct{}func (stu *Stduent) Speak(think string) (talk string) {    if think == "bitch" {        talk = "You are a good boy"    } else {        talk = "hi"    }    return}func main() {    var peo People = Stduent{}    think := "bitch"    fmt.Println(peo.Speak(think))}

The answer is no, prompt stduent does not implement people (Speak method has pointer receiver), the fix is var peo people = &stduent{}, assigned to the pointer

In the Go language, functions and methods are different, functions are not receivers, and methods are receivers and belong to a struct.

There are two types of recipients: value receivers (passed by value), pointer receivers (passed by pointer, may change incoming parameters)

Before I saw there was a place to explain: pointer receivers method can both transmit the value and can pass the pointer, including the value receivers method.

My previous understanding was also wrong.

This is not the case, value receivers and pointer receivers are clearly differentiated, people interface is value receivers, and student implements pointer Receivers the Speak method, so student did not implement Peple.

In fact, the pointer receivers method simply converts the M.speak () to (&m). Speak (), as mentioned in the official Go tour, the go compiler saves you a step to take the address.