The learning of pointers

The 1 pointer is passed as a parameter, but it is also a value pass, passing an address value (as with a normal value pass). When a value is passed, the function handles the parameter as a local variable of the function, which is the memory space on the stack to hold the parameter

void swap (int* A, int* b) {

int t = *a;

*a = *b;

*b = t;

}

This does not exchange A, b

void Swap1 (int* A, int* b) {

int* t = A;

A = b;

b = t;

}

2 char c[] = "AB" and char* p = "AB" are not the same

Char c[] = "AB" in "AB" is actually allocated on the stack, char* p = "AB" in "AB" is a constant pool assignment

sizeof (c) = 3 sizeof (p) = 4

Passed as a function parameter, the array is directly degraded to a pointer

The learning of pointers