The problem of preventing overflow in the use of binary lookup algorithm

Source: Internet
Author: User

The code on the wiki:

int binary_search (int a[], int key, int imin, int imax) {//Continue searching while [Imin,imax] is no T empty while (IMAX >= imin) {//Calculate the midpoint for roughly equal partition int imid = Midpoint (       Imin, IMAX);       if (a[imid] = = key)//key found at index IMiD return imid;        Determine which subarray to search else if (A[imid] < keys)//change min index to search upper Subarray      Imin = IMiD + 1;    else//Change Max index to search lower subarray IMAX = imid-1; }//key is not found return key_not_found;} 
The
uses two algorithms below.
 
int Binary_search () {int size;    Char keys[] = "9290"; Char words[][6] ={"1", "2", "+", "a", "222", "3", "5", "", "All", "};size", "The" "" "," "929," "" "", "" "" ",    );p rintf ("the first algorithm sizeof =%d\n", size);    int head = 0; int tail = size;int cursor = (head + tail)/2; int result = 999;int count = 0;printf ("keys= \"%s\ "\ n", keys);p rintf ("words[i][] = \ n"); for (int i = 0; i < size; ++i)    printf ("[%d]=\"%s\ "", I, words[i]);  do {result = strcmp (keys, words[cursor]);p rintf ("\ncount =%d cursor =%d head =%d, tail =%d, \ n", count++        , cursor, head, tail);p rintf ("words[%d] = \"%s\ ", result =%d \ n", cursor, words[cursor], result);        if (Result > 0) {head = cursor;        } else if (Result < 0) {tail = cursor;    }else{break;//find a matching key key combination}cursor = (head + tail)/2; } while (head < cursor) && (cursor <= tail); ((head <= cursor) && (cursor < tail)) printF ("\ n------------------\ncursor =%d head =%d, tail =%d, \ n", cursor, head, tail);p rintf ("words[%d] = \"%s\ ", result =%d \ n ", cursor, words[cursor], result);p rintf (" ====================\n "); int left = 0, right = size-1, middle = 0; , result = 0;count = 0;printf ("second algorithm sizeof =%d\n", size);p rintf ("keys= \"%s\ "\ n", keys);p rintf ("words[i][] = \ n"); for (int i = 0; i < size; ++i) printf ("[%d]=\"%s\ "", I, Words[i]);p rintf ("\nmiddle =%d, left =%d, right =%d, \ n", mid Dle, left <= right) {middle = (left + right) >> 1;result = strcmp (keys, Words[middle]);p rintf ( "Count =%d middle =%d, left =%d, right =%d, \ n", count++, middle, left, right);p rintf ("words[%d] = \"%s\ ", result =%d \ n ", middle, words[middle], result); if (Result > 0) {left = middle + 1;} else if (Result < 0) right = Middle-1;else break;} printf ("---------------------\nmiddle =%d, left =%d, right =%d, \ n", middle, left, right);p rintf ("words[%d] = \"%s\ " , result =%d \ n ", middle, words[middle], result); return cursor;}

The first algorithm sizeof = 12
keys= "9290"
Words[i][] =
[0]= "1" [1]= "2" [2]= "21" [3]= "22" [4]= "222" [5]= "3" [6]= "5" [7]= "66" [8]= "90" [9]
]= "900" [10]= "91" [11]= "929"
Count = 0 Cursor = 6 head = 0, tail = 12,
WORDS[6] = "5", result = 1

Count = 1 cursor = 9 head = 6, tail = 12,
WORDS[9] = "" ", result = 1

Count = 2 Cursor = Ten head = 9, tail = 12,
WORDS[10] = "a", result = 1

Count = 3 Cursor = One head = ten, tail = 12,
WORDS[11] = "929", result = 1

------------------
cursor = one head = one, tail = 12,
WORDS[11] = "929", result = 1


====================
The second algorithm sizeof = 12
keys= "9290"
Words[i][] =
[0]= "1" [1]= "2" [2]= "21" [3]= "22" [4]= "222" [5]= "3" [6]= "5" [7]= "66" [8]= "90" [9]
]= "900" [10]= "91" [11]= "929"
Middle = 0, left = 0, right = 12,
Count = 0 middle = 6, left = 0, right = 12,
WORDS[6] = "5", result = 1


Count = 1 middle = 9, left = 7, right = 12,
WORDS[9] = "" ", result = 1


Count = 2 middle = one, left = ten, right = 12,
WORDS[11] = "929", result = 1


---------------------
Middle = 12, left =.
WORDS[12] = "hot-hot 9290", result = 1
Please press any key to continue ...


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The problem of preventing overflow in the use of binary lookup algorithm

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