Memory search DP
After reading the online question solution, the state equation is really clever. orz
#include <cstdio>#include <cstdlib>#include <cmath>#include <set>#include <stack>#include <vector>#include <sstream>#include <cstring>#include <string>#include <map>#include <queue>#include <algorithm>#include <iostream>#define FFI freopen("in.txt", "r", stdin)#define maxn 210#define INF 0x3f3f3f3f#define inf 10000000#define MOD 1000000007#define ULL unsigned long long#define LL long long#define _setm(houge) memset(houge, INF, sizeof(houge))#define _setf(houge) memset(houge, -1, sizeof(houge))#define _clear(houge) memset(houge, 0, sizeof(houge))using namespace std;int dp[maxn][maxn][maxn];int a[maxn], n;int dfs(int l, int r, int k){ if(l > r) return 0; if(dp[l][r][k]) return dp[l][r][k]; dp[l][r][k] = dfs(l, r-1, 0) + (1+k)*(1+k); for(int i = r-1; i >= l; -- i) { if(a[r] == a[i]) { dp[l][r][k] = max(dp[l][r][k], dfs(l, i, k+1)+dfs(i+1, r-1, 0)); }} return dp[l][r][k];}int main() { FFI; int t, ca = 0; scanf("%d", &t); while(t --) { _clear(dp); scanf("%d",&n); for(int i = 1; i <= n; ++ i) scanf("%d", &a[i]); printf("Case %d: %d\n", ++ ca, dfs(1, n, 0)); } return 0;}