What is the benefit of using exit (0) in PHP to declare the exit status (successful exit or unexpected termination of a situation)? What's the difference between this and a direct exit?

Just like
The following code

echo '配置错误';exit(3);  //状态3表示由于配置错误而退出

And

// 直接退出exit('配置错误');

What's the difference?

Humbly ask the great God one or two

Reply content:

Just like
The following code

echo '配置错误';exit(3);  //状态3表示由于配置错误而退出

And

// 直接退出exit('配置错误');

What's the difference?

Humbly ask the great God one or two

Give the conclusion first: there are subtle differences.

To speak the truth or to take a document:

If status is a string, this function prints the status just before exiting.

If status is a integer, that value would be used as the exit status and not printed. Exit statuses should be in the range 0 to 254, the exit status 255 are reserved by PHP and shall not being used. The status 0 is used to terminate the program successfully.
note:php >= 4.2.0 does not print the status if it's an integer.

Simply put: If it is a string, it will print out, if it is a number, it will be the exit status code , will not be printed.

Executing the two lines of code separately, it is clear that the result is the same.

The difference is:
Comment on the second line, execute the following command at the terminal:
PHP test.php//print "error"
echo $? Printing 3

Comment on the first line, execute the following command at the terminal:
PHP test.php//print "error"
echo $? Printing 0

That is, Eixt () is used as an exit status code when the argument is of type int.
$? Explanation: Stores The exit value of the last command is executed (the exit state of the final one, 0 means no error).

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