Because a ^ 2 * B ^ 2 = (a * B) ^ 2, such: 2 ^ 2*3 ^ 2 = 4*9 = 36 = 6 ^ 2 = (2*3) ^ 2, so you can calculate the square root as follows:
Take 5 as an Example
From 1 ~ 9 increments to 2 ^ 25, so the first number is 2;
5/2 ^ 2 = 1.25;
From 1.1 ~ 1.9 increments to 1.1 ^ 21.25, so the second number is 1.1;
1.25/1.1 ^ 2 = 1.03305785. Do not use 1.0330 for reference. Actually, it is increased by two at a time;
From 1.01 ~ 1.09 increments to 1.01 ^ 21.0330, so the third number is 1.01;
1.25/1.1 ^ 2/1. 01 ^ 2 = 1.012702530379. do not refer to the following code. You can use 1.012702 as a reference and then increment it by two places;
From 1.001 ~ 1.009 increments to 1.006 ^ 21.012702, so the fourth number is 1.006;
The value we get so far is:
2*1.1*1.01*1.006 = 2.235332
......
If you want to be more accurate, you can calculate the result again. The calculator calculates 2.2360679774997896964091736687313, that is, you do not know how many times you have obtained the result, but no matter how you calculate it, it is also an approximate value, the square root of 5 is an infinitely non-repeating decimal number.
You can use a similar method to calculate any token such as the primary root and the fourth power root.
