Problem Description
"Palindrome string" is a literal reading and anti-read all the same string, such as "level" or "noon" and so on is a palindrome string. Please write a program to determine whether the read-in string is a "palindrome".
Input
The input contains multiple test instances, the first line of the input data is a positive integer n, which indicates the number of test instances followed by n strings. Each string length does not exceed 150.
Output
If a string is a palindrome, output "yes", otherwise output "no".
Sample Input
4
Level
Abcde
Noon
haha
Sample Output
Yes
No
Yes
No
1#include <stdio.h>2 3#include <string.h>4 5 intFunChara[])6 7 {       8 9          intI,k,r=1; Ten  OneK=strlen (a)-1;  A  -           for(i=0; I<=k;k--, i++)           -  the          {                 -  -                    if(a[i]!=A[k]) -  +                    {                           -  +R=0; A  at                              Break; -  -                    } -  -          } -  in          returnR; -  to } +  - intMain () the  * { $ Panax Notoginseng          Chara[ -]; -  the          intI,n; +  Ascanf"%d",&n); the  +           for(i=0; i<n;i++) -  $          { $  -scanf"%s",&a); -  the                    if(Fun (a) = =0) - Wuyiprintf"no\n"); the  -                    Else Wu  -printf"yes\n"); About  $          } -  -          return 0; -  A}
#include <stdio.h>#include<string.h>intMain () {Charstr[ -]; intn,i,j; scanf ("%d",&N);  while(n>0) {scanf ("%s", str); I=0; J=strlen (str)-1;  while(i<=j) {if(str[i]!=Str[j]) Break; I++; J--; }        if(i>j) printf ("yes\n"); Elseprintf ("no\n"); N--; }    return 0;}
Wuhan University of Science and Technology acm:1004:0 starting point algorithm 74--palindromes _easy version