ZOJ-3471 Most Powerful (State compression)

ZOJ-3471 Most Powerful (State compression)

There are n kinds of atoms. If two kinds of atoms collide, energy will be generated, and one of them will disappear. What is the maximum energy produced by these n kinds of atomic energy?

Solution: use 0 to indicate that the atom has not disappeared, and 1 to indicate that the atom has disappeared, so we can get the state transition equation.
Dp [state | (1 <I)] = max (dp [state | (1 <I)], dp [state] + power [j] [I])
The above equation indicates the maximum energy that can be obtained after the I atom disappears when the j atom is used to collide with the I atom.

Note: The generated energy may be negative.

#include
  
   #include#include
   
    using namespace std;#define N 15#define maxn 1200int power[N][N];int dp[maxn];int n;int main() {    while(scanf(%d, &n) != EOF && n) {        for(int i = 0; i < n; i++)            for(int j = 0; j < n; j++)                scanf(%d, &power[i][j]);        memset(dp, 0, sizeof(dp));        for(int i = 0; i < (1 << n); i++)            for(int j = 0; j < n; j++) {                if((i & (1 << j)))                    continue;                for(int k = 0; k < n; k++) {                    if(!(i & (1 << k)) && k != j) {                        dp[i | (1 << j)] = max(dp[i | (1 << j)], dp[i] + power[k][j]);                    }                }            }        int ans = 0;        for(int i = 0; i < (1 << n); i++)            ans = max(ans, dp[i]);        printf(%d, ans);    }    return 0;}