158A-Next Round

158A-Next Round
A. Next Roundtime limit per test3 secondsmemory limit per test256 megabytesinputstandard inputoutputstandard output

"Contestant who earns a score equal to or greater thanK-Th place finisher's score will advance to the next round, as long as the contestant earns a positive score... "-an excerpt from contest rules.

A totalNParticipant parts took part in the contest (N? ≥?K), And you already know their scores. Calculate how to adjust the participation to the next round.

Input

The first line of the input contains two integersNAndK(1? ≤?K? ≤?N? ≤? 50) separated by a single space.

The second line containsNSpace-separated integersA1 ,?A2 ,?...,?AN(0? ≤?AI? ≤? 100), whereAIIs the score earned by the participating ipant who gotI-Th place. The given sequence is non-increasing (that is, for allIFrom 1N? -? 1 the following condition is fulfilled:AI? ≥?AI? +? 1 ).

Output

Output the number of maid who advance to the next round.

Sample test (s) input

8 510 9 8 7 7 7 5 5

Output

6

Input

4 20 0 0 0

Output

0

Note

In the first example the particle ant on the 5th place earned 7 points. As the particle ant on the 6th place also earned 7 points, there are 6 advancers.

In the second example nobody got a positive score.

import java.util.*;public class Main {    public static void main(String[] args) {                Scanner sc=new Scanner(System.in);                    int n=sc.nextInt();            int k=sc.nextInt();            int count=0;        int[] score = new int[60];            for(int i=0;i
 
  =max&&score[i]>0)                    count++;            System.out.println(count);    }}