A quick way to make multiple character substitutions in Python summary _python

First the conclusion:

1. The number of characters to be replaced is not long, the direct chain method can be replace() replaced, the efficiency is very high;
   
2. If there are more characters to replace, it is recommended that the substitution be called in the For Loop replace() .

Feasible method:

1. Chain type replace ()

String.Replace (). Replace ()

1.x for calling replace() "when more characters are to be replaced" in the loop

2. Use of String.maketrans

3. First Re.compile and then Re.sub.

......

def a (text):
 chars = "&#" for
 C in chars:
 text = Text.replace (c, "\" + c)
def b (text): For
 ch in [' & ', ' # ']:
 if ch in text:
  text = text.replace (ch, "\" +ch)
import re
def c (text):
 rx = Re.compile (' ([&#]) ')
 text = rx.sub (R ' \\\1 ', text)
rx = Re.compile (' ([&#]) ')
def d (text):
 Text = rx.sub (R ' \\\1 ', text)
def mk_esc (esc_chars): Return
 lambda S: '. Join ([' \ ' + c if c in Esc_chars E LSE C for C in S])
ESC = Mk_esc (' &# ')
def e (text):
 ESC (text)
def f (text):
 text = Text.replac E (' & ', ' \& '). Replace (' # ', ' \# ')
def g (text):
 replacements = {"&": "\&", "#": "\#"}
 Text = "". Join ([Replacements.get (c, c) for C in text]
def h (text):
 text = Text.replace (' & ', R ' \& ')
 Text = Text.replace (' # ', R ' \# ')
def i (text):
 text = Text.replace (' & ', R ' \& '). Replace (' # ', R ' \# ')

Reference Links:

Http://stackoverflow.com/questions/3411771/multiple-character-replace-with-python

Http://stackoverflow.com/questions/6116978/python-replace-multiple-strings

Http://stackoverflow.com/questions/8687018/python-string-replace-two-things-at-once

Http://stackoverflow.com/questions/28775049/most-efficient-way-to-replace-multiple-characters-in-a-string

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