A small question

1?
0 ~~ 1 m

 

2) a computer has 16 characters in length and 2 MB in size. How can this problem be solved?
0 ~~ 2 m

Is there any relationship between the word length and the Word Length? What is the difference between the half-character and the word length? How can this problem be solved?

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Solution 1) 8 m/16 = 2 ^ 3*2 ^ 10*2 ^ 10/2 ^ 3 = 2 ^ 20 = 1 m, so the IP address of the hosts region is 0 ~ 1 m.

The solution is to use one address for each word, so that each address can contain eight characters. The word population is 8 Mb, so the formula is above.

 

Solution 2) the word length is 16, and the half-Address is used, that is, 8 storage units (just a word token) are used together with one address. The formula is as follows:
Capacity/number of characters that each address can access = maximum Address (2 m/1 = 2 m .......

 

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However, it was suggested that the word always belongs to 16 bits, and the character always belongs to the old man's family. If this method is used for calculation, it is:

One address is used for every two words, so one address is 16/8*2 = 4 characters, 16 Mb/4B = 4 m