about int &const T and int const& t

#include <iostream.h>
#include <stdio.h>

int main ()
{
int i = 0;
int const& j = i;
int & Const T = i;
const int& m = i;
i = 3;

printf ("j =%d m =%d T =%d i =%d &j =%d &m =%d &t =%d", j,m,t,i,&j,&m,&t);
GetChar ();
}

GCC compilation results:

int & Const T = i; does not pass

#include <iostream>
#include <stdio.h>


int main ()
{
int i = 0;
int const& j = i;
int & Const T = i;
Const int& m = i;
i = 3;
j=4;
m=5;


printf ("J =%d m =%d i =%d &j =%d &m =%d", j,m,i,&j,&m);
GetChar ();
}

GCC compiles the pass-through statement:

i = 3;
j=4;

#include <iostream>
#include <stdio.h>


int main ()
{
int i = 0;
int const& j = i;
int & Const T = i;
Const int& m = i;
i = 3;




printf ("J =%d m =%d i =%d &j =%d &m =%d", j,m,i,&j,&m);
GetChar ();
}

Output:

int const & J = I shows that j is a constant reference to int i, so this means that the value of I cannot be changed by T. However, since I is a variable, I can change the self-born value, and T is a reference to the variable I so she only refers to the value of variable I, so of course I change the value.

about int &const T and int const& t