ASP Date and Time Function example

ASP Date and Time Function example

You can use the date and time functions to obtain the date and time in various formats.

Function	Syntax	Description	Example
Now	Now ()	Obtain the current date and time of the system.	Dim myvar =Now 'MyvarContains the current date and time.
Date	Date ()	Obtain the current system date	Dim mydate =Date 'Mydate'Contains the current system date.
Time	Time ()	Obtain the current system time	Dim mytime =Time 'Returns the current system time.
Year	Year (date)	Get the year of a given date	Dim mydate, myyear Mydate = # October 19,196 2 # 'Assign a date. Myyear =Year (Mydate) 'Myyear'Include1962.
Month	Month (date)	Returns the month of a given date.	Dim myvar =Month (Now) 'Myvar contains the number corresponding to the current month.
Day	Day (date)	Returns the number of the given date.	Dim myday =Day ("October 19,196 2") 'Myday' includes19.
Hour	Hour (time)	The hour at which the given time is obtained	Dim mytime, myhour Mytime = now myhour =Hour (Mytime) 'MyhourContains the value representing the current time.
Minute	Minute (time)	Returns the number of minutes for a given time.	Dim myvar Myvar =Minute (Now)
Second	Second (time)	The number of seconds to obtain the token.	Dim mysec Mysec =Second (Now) 'MysecContains the number representing the current second.
Weekday	Weekday (date)	Returns the integer of the given date in the day of the week. 1 indicates Sunday, 2 indicates Monday, and so on.	Dim mydate, myweekday Mydate = # October 19,196 2 # 'Dispatch date Myweekday =Weekday (Mydate) 'MyweekdayInclude6. mydateFriday
Datediff	Datediff ("Var", var1, var2) VaR: date or interval factor, which has the following parameters: Yyyy, M, D, WW, week, H, S, seconds Var1: the first date or time Var2: second date or time, later than var1	Calculate the interval between two dates or times	Datediff ("D", date (), #1/1/2005 #) 'Return the number of New Year's Eve before 2005 Datediff ("H", date (), #1/1/2005 #) 'How many hours are there before 2005 New Year's Day? Datediff ("D", #1/1/2003 #, #1/1/2005 #) 'Returns the number of days between two dates.
Dateadd	Datediff ("Var", var1, var2) VaR: date or interval factor: Var1: date or interval multiple Var2: benchmark of date or time	Add two dates or times	In the following example, we will add a month to April January 31: Newdate =Dateadd ("M",1,"31-Jan-95") In this example,DateaddReturn February 28, instead of February 31. IfDateIf the value is January 31, the return value is February 29, because 1996 is a leap year. If the calculation date is before January 1, 100 AD, an error occurs.
Formatdatetime	Formatdatetime (date, vb1_date)	Convert to short Date Format	Fromatdatetime (date (), vblongdate) "Displayed in long Date Format
	Formatdatetime (date, vblongdate)	Convert to long Date Format
	Formatdatetime (date, vb1_time)	Convert to short time format
	Formatdatetime (date, vblongtime)	Convert to long time format