asp.net Transfer Parameter Method Summary _ Practical Tips

Before writing, assume that the first page is send.aspx and the second page is receive.aspx
1, through the URL link address delivery
(1) Send.asp code

Copy Code code as follows:

protected void Button1_Click (object sender, EventArgs e)
{
Request.redirect ("Default2.aspx?username=honge");
}

(2) Receive.aspx code

Copy Code code as follows:

String username = request.querystring["username"];//so that the parameter values can be obtained.

2, Post mode transmission
(1) Send.asp code

Copy Code code as follows:

<form id= "Form1" runat= "Server" action= "receive.aspx" method=post>
<div>
<asp:button id= "Button1" runat= "Server" onclick= "Button1_Click" text= "button"/>
<asp:textbox id= "username" runat= "server" ></asp:TextBox>
</div>
</form>

(2) Receive.aspx code

Copy Code code as follows:

String username = ruquest.form["Receive"];

3, Session mode transfer
(1) Send.asp code

Copy Code code as follows:

protected void Button1_Click (object sender, EventArgs e)
{
session["username"] = "Honge";
Request.redirect ("default2.aspx");
}

(2) Receive.aspx code

Copy Code code as follows:

String username = session["username"];//so that the parameter values can be obtained.

4, Application way to pass
(1) Send.asp code

Copy Code code as follows:

protected void Button1_Click (object sender, EventArgs e)
{
application["username"] = "Honge";
Request.redirect ("default2.aspx");
}

(2) Receive.aspx code

Copy Code code as follows:

String username = application["username"] so that the parameter values can be obtained.

5, the use of Server.Transfer for transmission
(1) Send.asp code

Copy Code code as follows:

public string Name
{
get {
return "Honge";
}
}
protected void Button1_Click (object sender, EventArgs e)
{
Server.Transfer ("default2.aspx");
}

(2) Receive.aspx code

Copy Code code as follows:

Send d = context.handler as send;
if (d!= null)
{
Response.Write (d.name);//This will get the parameter values.
}