C language problems

Source: Internet
Author: User
C language problems-General Linux technology-Linux technology and application information, the following is a detailed description. Question: enter two time points (in the 24-hour format) on the keyboard and output the time interval between the two time points. The time interval is represented by "hour: minute: Second.

Source code compiled by myself:
# Include
# Include


Int main (void)
{
Struct time {
Int h;
Int m;
Int s;
} Gap;
Int gapsec;

Int get_sec (void );

Gapsec = get_sec ();
Gapsec-= get_sec ();
Gap sec = (gap SEC> = 0 )? Gap SEC:-gap SEC;

Gap. h = gap SEC/3600, gap SEC % = 3600;
Gap. m = gap SEC/60, gap SEC % = 60;
Gap. s = gapsec;
Printf ("% d: % d \ n", gap. h, gap. m, gap. s );

Return 0;
}

Int get_sec (void)
{
Int I, j, totalsec = 0;
Char a [20], h [5], m [5], s [5], c;

For (I = 0; (c = getchar ())! = '\ N'; I ++)
A = C;
A= '\ 0 ';
For (I = 0, j = 0;! = ':'; I ++, j ++)
H [j] =;
H [j] = '\ 0 ';
Totalsec = atoi (h) * 3600;
For (I ++, j = 0;! = ':'; I ++, j ++ );
M [j] =;
M [j] = '\ 0 ';
Totalsec + = atoi (m) * 60;
For (I ++, j = 0;! = '\ 0'; I ++, j ++ );
S [j] =;
S [j] = '\ 0 ';
Totalsec + = atoi (s );
Return totalsec;
}

Problem: This code can be compiled on 64-bit ubuntu (12.04), but when debugging through gdb, the arrays m and s in the get_sec function cannot write the corresponding data, and the results are very strange, which of the following is my hope!

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