Compare Version Numbers

Compare Version Numbers

Compare numbers version1 and version1.
If version1 > version2 return 1, if version1 < version2 return-1, otherwise ret Urn 0.

Assume that the version strings is non-empty and contain only digits and the . character.
The . character does not represent a, decimal point and was used to separate number sequences.
For instance, was not "both and 2.5 a half" or "half-to-version three", it is the fifth Second-level revision of the S Econd first-level revision.

Here are an example of version numbers ordering:

0.1 < 1.1 < 1.2 < 13.37

1  Public classSolution {2      Public intcompareversion (String version1, String version2) {3String ver1_ch[] = version1.split ("\ \."));4String ver2_ch[] = version2.split ("\ \."));5                6         inti = 0;7          for(; i < ver1_ch.length && I <ver2_ch.length; i++){8             9             if(Integer.valueof (Ver1_ch[i]) >integer.valueof (Ver2_ch[i]))Ten                 return1; One             Else if(Integer.valueof (Ver1_ch[i]) <integer.valueof (Ver2_ch[i])) A                 return-1; -         } -         if(I >= ver1_ch.length && i >=ver2_ch.length) the             return0; -         Else if(I >=ver1_ch.length) { -              for(; i < ver2_ch.length; i++){ -                 if(Integer.valueof (ver2_ch[i]) > 0) +                     return-1; -             } +             return0; A         } at         Else -         { -              for(; i < ver1_ch.length; i++){ -                 if(Integer.valueof (ver1_ch[i]) > 0) -                     return1; -             } in             return0; -         } to     } +}

Compare Version Numbers