Console outputs spiral numbers

First and finally

 

 

Make a spiral numeric output for the specified array size of the input:

Assume input 3 and output as follows:

1 2 3

8 9 4

7 6 5

 

 

In this order.

 

The implementation code is as follows:

1 # include <iostream>
2 # include <iomanip>
3 using namespace STD;
4
5 void inputgrid (int n, int * m)
6 {// n indicates the scale. M is a two-dimensional array pointer.
7 int ROW = 0, line = 0, flag = 0; // row, line indicates the number of rows or columns to be processed;
8 int I = 0, j =-1;
9 For (INT num = 1; num <= N * n ;)
10 {
11 if (! Flag)
12 {
13 // Line Processing
14 int addnum;
15 if (row % 2 = 0) addnum = 1; // go forward
16 else addnum =-1; // go back
17 int num_row = N-row;
18 while (num_row)
19 {// fill all the remaining blank columns of the row
20 num_row --;
21 J + = addnum;
22 * (m + n * I + J) = num;
23 num ++;
24}
25 row ++;
26 flag = 1;
27
28}
29 else
30 {
31 // column Processing
32 int addnum;
33 If (line % 2 = 0) addnum = 1; // go forward
34 else addnum =-1; // go back
35 int num_line = n-line-1;
36 while (num_line)
37 {// fill all the remaining blank items in this column
38 num_line --;
39 I + = addnum;
40 * (m + n * I + J) = num;
41 num ++;
42}
43 line ++;
44 flag = 0;
45}
46}
47/* For (INT I = 0; I <n * n; I ++)
48 {
49 * (m + I) = I;
50 }*/
51}
52
53 int main ()
54 {
55 int n = 1;
56 int * m, * TM;
57 while (n! =-1)
58 {
59 cout <"Enter the number of rounds: (enter-1 to exit )";
60 CIN> N;
61 If (n =-1)
62 Return 0;
63 m = (int *) malloc (N * n * sizeof (INT ));
64 inputgrid (n, m );
65 for (INT I = 0; I <n; I ++)
66 {
67 TM = m + n * I;
68 for (Int J = 0; j <n; j ++)
69 {
70 cout <SETW (3) <* (TM + J) <"";
71}
72 cout <"\ n ";
73}
74}
75 // return 0;
76}