Count the frequency in a specific file

Finding the frequency of words used in a file is a very interesting thing, and we use associative arrays, awk,sed,grep, and so on to solve the problem in different ways.

First, we need a test text to save the name Word.txt

The contents are as follows:

Word used  
This  counting  

Next you need to write a shell script, as follows:

#!/bin/bash  
#Name: word_freq.sh  
#Description: Find out frequency of words in a file  
      
if [$#-ne 1];  
Then  
    echo "Usage: $ filename";  
    Exit-1
fi  
      
filename=$1
      
egrep-o "\b[[:alpha:]]+\b" $filename | \
      
awk ' {count[$0]++} end{printf ("%- 14s%s\n "," Word "," Count "); \ 
 for (Ind in count) {printf ("%-14s%d\n", Ind,count[ind]);} '

Work Principle Introduction:

1.egrep-o "\b[[:alpha:]]+\b" $filename used to output only words, with the-O option to print out a sequence of matched characters separated by line breaks so that we can list one word per line

2.\b is a word boundary marker. [: Alpha:] is the character class that represents the letter

The 3.awk command is used to avoid iterating over each word

A screenshot of the operation is given below:

Please refer to the blogger's other blogs about the awk command.