Count the number of words in a string

1, simple statistics of the number of words, words and words only consider the case of space

//word_statistic.cpp: Defines the entry point of the console application. //#include"stdafx.h"#include<iostream>#include<string>using namespacestd;#defineM 10000#defineN 20int_tmain (intARGC, _tchar*argv[]) {    Charstr1[m]={0}; CharStr2[m][n]; intCount[m];    Gets (STR1); cout<<"The string you entered is:"<<str1<<Endl; intLen=strlen (STR1);//only the Strlen function can be used here, and the sizeof function will output the length of the entire array instead of the actual number of characters in the array .    intj=0, i=0, k=0;  while(j<Len) {         while(str1[j]== +)//The if statement is not used here to use the while loopJ + +;  while(j<len&&str1[j]!= +)//J<len is important. Otherwise the last word of the statistic string is executed until the end of the stringstr2[i][k++]=str1[j++]; STR2[I][K]=' /';//count[i]=1;//Word Count         for(intp=0;p <i;p++)//Note that the scope of the For loop has persisted to k=0; the Code            if(strncmp (str2[p],str2[i],n) = =0)//returns 0 only if the first n characters are equal{Count[p]++;//Note that this is count[p]++, not count[i]++ .i--;//The current word is already duplicated so the current word is not counted into the str2 array                 Break; } I++; K=0; }    //Output Results     for(intq=0; q<i;q++) {cout<<str2[q]<<"\ t"<<count[q]<<Endl; }    return 0;}

The above code only consider the case of space between words, can be added to consider is a space, comma, period.

 while (str1[j]==| | str1[j]==| | str1[j]==)    // This is a while loop where you  cannot use the IF statement            j + +;          while (j<len&&str1[j]!=&&str1[j]!=-&&str1[j]!=)    // J<len is important.  otherwise the last word of the statistic string is executed until the  end of the string            str2[i][k++]=str1[j++];

You can change it for a second.

Here's a question for Huawei:

Title Description:

Enter a section of English text, using the program to statistics the highest and lowest frequency of two words;

Only these four types of characters appear in the English text: space (), comma (,), English period (.), English uppercase and lowercase letters (A-Z, A-Z)

The delimiters between words only consider these three kinds: space (), comma (,), English period (.);

The same word is counted only in the case of different words;

If two words occur the same number of occurrences, the first occurrence of the word in the text returns first.

Returned words are returned uniformly in lowercase letters

For example:

Input string "Hello world, I said hello World", Return "world", "I"

Input string "Somebody like somebody,i don't like it", return "Somebody", "I"

Required implementation functions:

void Wordstat (const char * pinputstr, char * poutputhotword, char * poutputcoldword);

//count the most occurrences and fewest words in a string pinputstrvoidWordstat (Const Char* Pinputstr,Char* Poutputhotword,Char*Poutputcoldword) {    intlen=strlen (PINPUTSTR); intj=0, i=0, k=0; Chardst[10000][ -]; intcount[10000];  while(j<Len) {         while(pinputstr[j]== +|| pinputstr[j]== -|| pinputstr[j]== $) J++;  while(j<len&&pinputstr[j]!= +&&pinputstr[j]!= -&&pinputstr[j]!= $) Dst[i][k++]=pinputstr[j++]; DST[I][K]=' /'; Count[i]=1;  for(intp=0;p <i;p++)            if(STRNCMP (Dst[i],dst[p), -)==0) {Count[p]++; I--;  Break; } I++; K=0; }    intmax=count[0]; intmax_flag=0; intmin=count[0]; intmin_flag=0; intF;  for(f=0; f<i;f++)    {        if(max<Count[f]) {Max=Count[f]; Max_flag=F; }        if(min>Count[f]) {min=Count[f]; Min_flag=F; }} cout<<dst[max_flag]<<"\ t"<<max<<Endl; Poutputhotword=Dst[max_flag]; cout<<dst[min_flag]<<"\ t"<<min<<Endl; Poutputcoldword=Dst[min_flag];}

Count the number of words in a string