Doubts about the deviation of the landing point

Source: Internet
Author: User

The classical method of landing point deviation is to calculate the longitudinal and transverse deviations by the unitary radius and the angle deviation, if the location and target points are near, can make use of the emission system three coordinates directly to do the difference, the square, the sum, then the root, namely

L=sqrt ((x1-x2) ^2+ (y1-y2) ^2+ (Z1-Z2) ^2)

is the deviation from the longitudinal and transverse deviations corresponding to this figure?

I use the formula to calculate the deviation of 50 meters, but the use of the unitary method is a few kilometers away, is very confused ...

The firing system is rotated, is the error of the upper type so large?

Doubts about the deviation of the landing point

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