Finds whether the specified character exists in the string

Compiler: dev++

Important: If the direct output string array a[20], then write printf ("%s", &a), you need to add the address character, if the output of a single array element, do not take the address character printf ("%c", &a[i]);

#include <stdio.h>
int main ()
{
Char A[100],num;
int i,flag=0;
printf ("Enter a string:");
Gets (a);
printf ("Enter the characters you want to find:");
scanf ("%c", &num);
for (i=0;a[i]!= ' n '; i++)
{
if (a[i]==num)
{
printf ("character%d of string%s is the character you want to find%c\n", &a,i+1,num);
flag=1;
}
}
if (flag==0)
printf ("character%c\n not present in string%s", &a,num);
}

Finds whether the specified character exists in the string