Function.prototyoe.call.apply

It was interesting to see someone ask Function.prototype.call.apply (obj, args) How to understand it in a group. Just started by the inertial thinking interference, has been called and apply separate use AH!!!

If you understand [].slice.apply (obj, args), you can understand Function.prototype.call.apply (obj, args).

Because of the "." The sequence of operations is from right to left, so

(1) First to the right of the "." For the split point, the Obj1=function.prototype.call on the left is a whole, calling obj1.apply (obj, args);

(2) after replacing it with obj, it becomes obj.call (Args[0], args[1], ...) ；

(3) Replace the action again, become Args[0] (args[1], ...);

That's it.

Function.prototyoe.call.apply