How do convert large HEX string to binary array?

Source: Internet
Author: User

How convert large HEX string to binary

I have a string with characters. This is a hex represantation of 7bytes. I want to convert it to binary.

int32_t Hex2bin (uint8_t * phexstring, uint8_t *Pbinarray) {  into =0; inti =0;  while(phexstring[i]! =0x00 )  {    Switch(phexstring[i]) { Case '0': pbinarray[O]=0x00;  Break;  Case '1': pbinarray[O]=0x10;  Break;  Case '2': pbinarray[O]=0x20;  Break;  Case '3': pbinarray[O]=0x30;  Break;  Case '4': pbinarray[O]=0x40;  Break;  Case '5': pbinarray[O]=0x50;  Break;  Case '6': pbinarray[O]=0x60;  Break;  Case '7': pbinarray[O]=0x70;  Break;  Case '8': pbinarray[O]=0x80;  Break;  Case '9': pbinarray[O]=0x90;  Break;  Case 'A':       Case 'a': pbinarray[O]=0xa0;  Break;  Case 'B':       Case 'b': pbinarray[O]=0xb0;  Break;  Case 'C':       Case 'C': pbinarray[O]=0xc0;  Break;  Case 'D':       Case 'D': pbinarray[O]=0xd0;  Break;  Case 'E':       Case 'e': pbinarray[O]=0xe0;  Break;  Case 'F':       Case 'F': pbinarray[O]=0xf0;  Break; default:        return-1; }    if(phexstring[i +1] ==0x00 )      return-1; Switch(phexstring[i +1 ] )    {       Case '0': pbinarray[O]|=0x00;  Break;  Case '1': pbinarray[O]|=0x01;  Break;  Case '2': pbinarray[O]|=0x02;  Break;  Case '3': pbinarray[O]|=0x03;  Break;  Case '4': pbinarray[O]|=0x04;  Break;  Case '5': pbinarray[O]|=0x05;  Break;  Case '6': pbinarray[O]|=0x06;  Break;  Case '7': pbinarray[O]|=0x07;  Break;  Case '8': pbinarray[O]|=0x08;  Break;  Case '9': pbinarray[O]|=0x09;  Break;  Case 'A':       Case 'a': pbinarray[O]|=0x0a;  Break;  Case 'B':       Case 'b': pbinarray[O]|=0x0b;  Break;  Case 'C':       Case 'C': pbinarray[O]|=0x0c;  Break;  Case 'D':       Case 'D': pbinarray[O]|=0x0d;  Break;  Case 'E':       Case 'e': pbinarray[O]|=0x0e;  Break;  Case 'F':       Case 'F': pbinarray[O]|=0x0f;  Break; default:        return-1; } I+=2; o++; }  returno;}

How do convert large HEX string to binary array?

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