How does Ajax find the servlet path through a URL? __ajax

Source: Internet
Author: User
Tags sort

Recently want to use AJAX to achieve level three, but when the URL of the servlet, Xmlhttpreq.status returned 404, that is, the Servlet,url path error is not found.

This is how I configured it in Web. Xml.

<servlet-mapping>
<servlet-name>AjaxServlet</servlet-name>
<url-pattern>/dyList</url-pattern>
</servlet-mapping>

var url = "dylist?sort=" + sort;

alert (URL);

Workaround

String path = Request.getcontextpath (); String basepath = request.getscheme () + "://" +request.getservername () + ":" +request.getserverport () +path+ "/"; System.out.println ("Path:" + path);

Change the URL into

var url = "<%=basepath%> dylist?sort=" + sort;

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