How to get the time difference of date by the granularity of JS

Get Date Type

var type = _xaxis[0].split (/-|:| \s/). length;

Gets the time difference of a date by granularity

    functionGetdatediffbytype (newdate,enddate,type) {newdate=NewDate (newdate) = = ' Invalid date '? Newdate+ ': 00 ': newdate; EndDate=NewDate (endDate) = = ' Invalid date '? Enddate+ ': 00 ': endDate; varDateDiff =NewDate (endDate)-NewDate (newdate); var_date =NewDate (DateDiff); varYear = _date.getfullyear ()-1970; varmonth =_date.getmonth (); Switch(type) { Case1: {                returnYear ;  Break; }             Case2: {                returnMonth+year*12;  Break; }             Case3: {                returnDatediff/1000/60/60/24;  Break; }             Case4: {                returnDATEDIFF/1000/60/60; Break; }             Case5: {                returnDatediff/1000/60;  Break; }             Case6: {                returndatediff/1000; Break; }        }    } 　 

Attached: date is formatted by time granularity

function Datefmtbytype (_date,_type) {_date = new Date (_date) = = ' Invalid date '? _date+ ': xx ': _date;//"2017-02-12 12" is in Valid Datevar date = new Date (_date), var fmt = ["yyyy", "yyyy-mm", "Yyyy-mm-dd", "Yyyy-mm-dd hh", "Yyyy-mm-dd hh:mm", " Yyyy-mm-dd hh:mm:ss "];return Date.dateformat (Fmt[_type-1]);}

Attached: Date format code ("Yyyy-mm-dd hh:mm:ss")

Date.prototype.dateFormat = function (FMT)   {//author:meizz     var o = {       "m+": This.getmonth () +1,                 //month       "d+": this.getdate (),//                    day       "H +": this.gethours (),                   //hour       "m+": This.getminutes (),       //min "S+": This.getseconds (),                 //sec       "q+": Math.floor ((This.getmonth () +3)/3),//quarterly       "s"  : This.getmilliseconds ()             //msec     };     if (/(y+)/.test (FMT))       Fmt=fmt.replace (regexp.$1, (this.getfullyear () + ""). substr (4-regexp.$1.length));     For (var k in O)       if (New RegExp ("(" + K + ")"). Test (FMT))     FMT = Fmt.replace (regexp.$1, (regexp.$1.length==1)? (O[k]): (("XX" + o[k]). substr (("" + O[k]).));     return FMT;   

　　

How to get the time difference of date by the granularity of JS