PHP Gets the odd even number of PHP judgements per week 6th

Requirements Description: According to the date of every Saturday to determine whether it is bi-weekly, weekly, that is, if the date of Saturday is the singular, then this week is a single break, if it is even, that is double Hugh. Before taking into account the difference in the number of days per month, the judgment is not very accurate and has been modified, and is now accurate. Example, PHP gets the odd even implementation code of PHP judgment for the 6th period of each week. $ts =date (' t ');//Get total number of days of the month $rq =date (' d ');//Get today's date $xq =date (' W ');//Get today's week, 1-6 for week 1-6, 0 for Sunday Calculate the number of days from Saturday if ($xq ==6) { $date 1 = 0; }else if ($xq ==0) { $date 1 =-1; }else{ $date 1= 6-$xq;} Use the current date plus the number of days from Saturday $RQ = $rq + $date 1; Compare with the total number of days of the month if ($rq <= $ts) { $RQ = $RQ; }else if ($rq > $ts) { $RQ = $rq-$ts; }else{ $RQ = $date 1; } bbs.it-home.org The date of the Saturday is calculated, and then the date is judged by an odd even number. $a = $RQ; $a = $a% 2; if ($a ==0) { Echo ' This Saturday is: '. $rq. ', this week is two weeks '; } else{ Echo ' This Saturday is: '. $rq. ', this week is one week '; } ?> Copy Code

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