PHP Paging code error, (only the last 27 points left)

PHP Paging code error, consult a master. (Only the last 27 points left)
The result is the first page that displays only the contents of the database, and clicking the next page still stays on the first page.

 
  $pages =ceil ($count/$list _num);
    echo "


















 
  
  "; if ($offset) {$preoffset = $offset-$list _num;print " 
     ";} else {echo ' 
     ";} $newoffset = $offset + $list _num; if ($pages!=0) && (($newoffset/$list _num)! = $pages)) {print (" 
     ");} else{echo " 
     ";} $pageno = ($offset/$list _num) +1;echo " 
     
          
  
   
   
 
    
 
     
 
     
Total ". $pages." Page
Previous page
Previous page
Next page
Next page
ThePage
 
     
 
    
 
   
 
  
  
";
   ?>

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------Solution--------------------
As for the SQL statement of the database, I'm not quite sure how it was written.
Typically select * from ' table ' ORDER BY id DESC LIMIT 1 $offset * $count/$list _num, ($offset + 1) * $count/$list _num
The following code has been tested with my own database and can be run

!--? php
if ($_get[offset]) {
 $offset = $_get[offset]; 
} 
 $count = 100; 
 $list _num = 5; 
 $pages =ceil ($count/$list _num); 
 Echo 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
             
   
 
  
   "; if ($offset) {$preoffset = $offset-1; Print " 
     "; } $newoffset = $offset +1;//$list _num; if ($pages!=0) && (($newoffset/$list _num)! = $pages)) {print (" 
     
 
   
   
 
    
 
     
 There are currently ". $count." Record 
 
     
 total. "$pages." Page 
";} else {echo "
 
     
 previous page 
");