Pointers in the C language

Let's look at pointers in C + +, which is just an extension

Array pointers

In fact, the main point here is the pointer operation in C + +

  /* Array element pointer:    A variable has an address, an array contains several elements, each array element has a corresponding address, and a    pointer variable can point to an array element (the address of an element is placed in a pointer variable)    A pointer to an array element is an array element whose address    can be pointed to an array element     int a[10]={1,2,3,4,5,6,7,3,2,3} with a pointer variable;        int *p;        p=&a[0]; Equivalence and p=a; equivalent to int *p=a; Equivalence with int*p=&a[0]     Note:    1) The array name A does not represent the entire array, only the address of the first element of the array       p=a is "Assigning the address of the first element of a array to the pointer variable P" instead of "assigning the value of each element of the array A to P"   array Pointers: pointer    array pointers to array elements:    using an array pointer to indirectly access the array pointer's definition of an element array:    int *p; array pointer initialization;     int a[4] ={1,2,3,4};    int *p = a;//array pointer, defines the first address of a pointer variable p assignment array (the address of the first element), p points to the first element of the array        int *p = &a[0];//equivalent to the above sentence  array pointer How to access the elements of the array:    1) p+1 represents the next element to the array    2) p-1 points to the previous element of the array  error: Iterating the array for    (int i=0;i<4; i++) {        printf ( "%d\t", *p++);    }     The misunderstanding of Learning: array name A is a constant equivalent to * (10++)    //array name + + This is the wrong    printf ("*a=%d\n", *a++);//The notation is wrong   */

　　

Pointers in the C language