Poj 1019 Number Sequence binary

Source: Internet
Author: User

Poj 1019 Number Sequence binary
Number Sequence

Time Limit:1000 MS Memory Limit:10000 K
Total Submissions:34391 Accepted:9879

Description

A single positive integer I is given. write a program to find the digit located in the position I in the sequence of number groups S1S2... sk. each group Sk consists of a sequence of positive integer numbers ranging from 1 to k, written one after another.
For example, the first 80 digits of the sequence are as follows:
11212312341234512345612345671234567812345678912345678910123456789101112345678910

Input

The first line of the input file contains a single integer t (1 ≤ t ≤ 10), the number of test cases, followed by one line for each test case. the line for a test case contains the single integer I (1 ≤ I ≤2147483647)

Output

There shoshould be one output line per test case containing the digit located in the position I.

Sample Input

283

Sample Output

22


#include
 
  #include
  
   #include
   
    using namespace std;typedef long long ll;const ll maxn=40000;ll a[maxn],b[maxn];void init(){    a[1]=b[1]=1;    for(ll i=2;i
    
     >T;    while(T--){        ll n;        cin>>n;        cout<
     
      


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