Python dictionary sort

We all know that dictionaries are unordered, how do we sort them according to the dictionary key or value?

Sort by key of the dictionary

Available in three ways:
1. Using lambda

>>> a = {‘b‘:‘a‘,‘d‘:‘d‘,‘a‘:‘a‘}>>> sorted(a.items(),key=lambda x:x[0])[(‘a‘, ‘a‘), (‘b‘, ‘a‘), (‘d‘, ‘d‘)]

2. Using operator module

>>> import operator>>> sorted(a.items(),key=operator.itemgetter(0))[(‘a‘, ‘a‘), (‘b‘, ‘a‘), (‘d‘, ‘d‘)]

3. Direct use of sorted
The dictionary key is sorted by default

>>> sorted(a.items())[(‘a‘, ‘a‘), (‘b‘, ‘a‘), (‘d‘, ‘d‘)]

Sort by value of dictionary

Available in two ways:
1, use lambda, change the index can be

>>> a = {‘a‘:‘d‘,‘b‘:‘a‘,‘c‘:‘b‘}>>> sorted(a.items(),key=lambda x:x[1])[(‘b‘, ‘a‘), (‘c‘, ‘b‘), (‘a‘, ‘d‘)]

2, the use of operator, but also change the index can be

>>> import operator>>> sorted(a.items(),key=operator.itemgetter(1))[(‘b‘, ‘a‘), (‘c‘, ‘b‘), (‘a‘, ‘d‘)]

It is important to note that sorted () does not change its value by default, just return a result

Just wrap it up with the Dict function:

>>> a = dict(sorted(a.items(),key=lambda x:x[0]))>>> a{‘a‘: ‘d‘, ‘b‘: ‘a‘, ‘c‘: ‘b‘}

Python dictionary sort