Regular Expressions-PHP regular substitution problem

My regular comparison dish, there is now a regular replacement of the problem has been uncertain, the demand is this:

Some of the tags in the content

（这里有任意内容和标签）（ 这里也有任意内容和标签）

Then the item is replaced with this:

（这里有任意内容和标签）（ 这里也有任意内容和标签）
  
   

Simply said that the img outside the bread figure and then pulled out to put behind p, and then use preg_replace how to write it?

Reply content:

My regular comparison dish, there is now a regular replacement of the problem has been uncertain, the demand is this:

Some of the tags in the content

（这里有任意内容和标签）（ 这里也有任意内容和标签）

Then the item is replaced with this:

（这里有任意内容和标签）（ 这里也有任意内容和标签）
  
   

Simply said that the img outside the bread figure and then pulled out to put behind p, and then use preg_replace how to write it?

Can I understand that

• Extract all the img tags under p to p, if it is multiple img, this needs to use Preg_match.

• And there will be other labels in p, except P tags

If there's only one img inside,

//正则$p = '#
  <>
 .*?)>(?  .*?)(?\)(?  .*?)  
#i';//替换$r = '  $2$4 
 
   
    
       $3
      
   ';//原内容$s = '
      
fsdfsdfsfkolja;ad;lasd
';echo preg_replace($p, $r, $s);// 结果：// 
      
fsdfsdfsfkolja;ad;lasd
      
   
     
    
   
  

There are multiple img

$s = '
fsdfsdfsfkolja;ad;lasd
asdaa
';echo preg_replace_callback('# <>
 .*?)>(?  .*?) 
#', function($matches) { preg_match_all('##', $str = $matches[0], $matches1, PREG_OFFSET_CAPTURE ); foreach (array_reverse($matches1[0]) as $v) $str = substr_replace($str, '', $v[1], strlen($v[0])); return $str.' 
   
    
     '.implode('',array_map(function($v){return $v[0];}, $matches1[0])).'
    
   ';}, $s);// 结果：// 
    
fsdfsdfsfkolja;ad;lasd
    
   asdaa
    
 
   
   
  

