Remove the contents (including double quotes) between paired double quotes

Problem:

The contents of a line in the text contain pairs of double quotation marks, which may be several pairs, as shown in the following example.

LOG ("ABCDE");

ABC "DEF", "Hat" hij

134 "TLH" 567 "Xzt" 789

It is now required to remove the contents of the paired double quotes (including double quotes) and expect the results to be as follows.

LOG ();

Abc,hij

134567789

Answer:

Sed-r ' s/' [^ ']* '//g ' file
LOG ();
Abc,hij
134567789

awk ' {gsub (/"[^"]* "/," ");p rint} ' file
LOG ();
Abc,hij
134567789

This article is from the "Eight Miles" blog, so be sure to keep this source http://5921271.blog.51cto.com/5911271/1772042

Remove the contents (including double quotes) between paired double quotes