"Seemingly challenging" shell how to get the value of return in PHP

"Seemingly challenging" how the shell gets the value of return in PHP
Title PHP This file is to return an array

PHP Code

  
   
  
   ' 1 ',  ' b ' = ' 2 ',  ' c ' = ' public ',  ' d ' = ' ', '  e ' = = ', '; >

In the shell how to receive this array ah or there is no way

------Solution--------------------

PHP Code

[User:root time:07:23:08 path:/home/liangdong/php]$ php a.php Array ([a] + 1 [b] = 2 [c] = Public [d] = [E] = [User:root time:07:23:10 path:/home/liangdong/php]$ Cat a.php
  [User:root time:07:23:12 path:/home/liangdong/php]$ Cat b.php
  ' 1 ', ' b ' = ' 2 ', ' c ' = ' public ', ' d ' = ' ', ' e ' = = ', '; >
------Solution--------------------
The shell is not ripe, estimate your needs I will use later, studied one,


  
  

   
   

     PHP Code 
    
#!/bin/basheval ' cat php_data.txt |grep ' = ' |tr-d ', >\ ' "|xargs-i {} echo {}\;|tr" \ n "" "' Echo ${a}echo ${b}echo ${c}echo ${d}
------Solution--------------------
Cross-language data exchange requires a data structure that can be recognized by both parties,
Otherwise it doesn't make sense.

If you have a sample PHP code that is pre-compiled by Zend, or is being disturbed by a shield (you cannot say that he is not a PHP file)
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